5x^2-10x=26

Solution for 5x^2-10x=26 equation:

5x^2-10x=26

We move all terms to the left:

5x^2-10x-(26)=0

a = 5; b = -10; c = -26;
Δ = b2-4ac
Δ = -102-4·5·(-26)
Δ = 620
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{620}=\sqrt{4*155}=\sqrt{4}*\sqrt{155}=2\sqrt{155}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{155}}{2*5}=\frac{10-2\sqrt{155}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{155}}{2*5}=\frac{10+2\sqrt{155}}{10}
$